Question

use the functions f(x)= -x² + 8x -11 and g(x)= 14-⅔x½g(-6) + f(-2)

Answer 1

$\begin{gathered} f(x)=-x^2+8x-11 \\ g(x)=14-\frac{2}{3}x \end{gathered}$$\begin{gathered} \frac{1}{2}g(-6)=\frac{1}{2}(14-\frac{2}{3}(-6))=\frac{1}{2}(14+4)=\frac{18}{2}=9 \\ f(-2)=-(-2)^2+8(-2)-11=-4-16-11=-31 \end{gathered}$

Therefore:

$\frac{1}{2}g(-6)+f(-2)=9-31=-22$