Question

write the next 4 sequence start at 5 3/4, subtract 5/8

Answer 1

Subtract 5/8 from 5 3/4 to obtain the first term.

$\begin{gathered} 5\frac{3}{4}-\frac{5}{8}=\frac{23}{4}-\frac{5}{8} \\ =\frac{46-5}{8} \\ =\frac{41}{8} \\ =5\frac{1}{8} \end{gathered}$

Subtract 5/8 from 41/8 to obtain the second term.

$\begin{gathered} \frac{41}{8}-\frac{5}{8}=\frac{41-5}{8} \\ =\frac{36}{8} \\ =\frac{9}{2} \\ =4\frac{1}{2} \end{gathered}$

Subtract 5/8 from 36/8 to obtain the third term.

$\begin{gathered} \frac{36}{8}-\frac{5}{8}=\frac{36-5}{8} \\ =\frac{31}{8} \\ =3\frac{7}{8} \end{gathered}$

So first four terms are,

$5\frac{3}{4},5\frac{1}{8},4\frac{1}{2},3\frac{7}{8}$