Question

Part A) log₂ (x) = 6x=Part B) 9² = 612x=Part C) In(x) = 3.5x =

Answer 1

Given:

$\log_2x=6$

Required:

To find the value of x.

Explanation:

We know that

$\begin{gathered} \log_ax=b \\ \\ x=a^b \end{gathered}$

Consider

$\begin{gathered} \log_2x=6 \\ \\ x=2^6 \\ \\ x=64 \end{gathered}$

Final Answer:

$x=64$