We have that the sum of interior angles of every quadrilateral equals 360. Then, in this case, we have the following equation:
[tex]110+90+x+10+2x=360[/tex]
solving for x, we get:
[tex]\begin{gathered} 110+90+x+10+2x=360 \\ \Rightarrow210+3x=360 \\ \Rightarrow3x=360-210=150 \\ \Rightarrow x=\frac{150}{3}=50 \\ x=50 \end{gathered}[/tex]
therefore, x = 50
