Respuesta :
Answer:
[tex]x=\frac{-5\pm\sqrt{21} }{2}[/tex]
Step-by-step explanation:
We use the quadratic formula here which says for a quadratic equation [tex]ax^2+bx+c=0[/tex].
[tex]x= \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Now in our case
[tex]a=1\\b=5\\c=1[/tex]
so we have:
[tex]x=\frac{-5\pm\sqrt{5^2-4(1)(1)} }{2(1)} =\frac{-5\pm\sqrt{21} }{2}[/tex]
[tex]\boxed{x=\frac{-5\pm\sqrt{21} }{2} }[/tex]
Which are our solutions.
Answer:
B
Step-by-step explanation:
The quantity of 5 plus or minus the square root of 21 all over 2.
FURTHER EXPLANATION: I took the practice test and got it right.