Respuesta :

Part 1

Find out the value of sin(theta)

[tex]\sin (\theta)=\frac{24}{25}[/tex]

By opposite side divided by the hypotenuse in a right triangle

Part 2

Find out cos(theta)

Remember that

[tex]\sin ^2(\theta)+\cos ^2(\theta)=1[/tex]

substitute the value of sine

[tex](\frac{24}{25})^2+\cos ^2(\theta)=1[/tex][tex]\cos ^2(\theta)=1-\frac{576}{625}[/tex][tex]\begin{gathered} \cos ^2(\theta)=\frac{49}{625} \\ \\ \cos ^{}(\theta)=\frac{7}{25} \end{gathered}[/tex]

Part 3

Find out the value of tan(theta)

[tex]\tan (\theta)=\frac{\sin (\theta)}{\cos (\theta)}[/tex]

substitute given values

[tex]\tan (\theta)=\frac{24}{7}[/tex]

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