Find the values of sin, cos, and tan for the given right triangle. Give the exact values.

Part 1
Find out the value of sin(theta)
[tex]\sin (\theta)=\frac{24}{25}[/tex]By opposite side divided by the hypotenuse in a right triangle
Part 2
Find out cos(theta)
Remember that
[tex]\sin ^2(\theta)+\cos ^2(\theta)=1[/tex]substitute the value of sine
[tex](\frac{24}{25})^2+\cos ^2(\theta)=1[/tex][tex]\cos ^2(\theta)=1-\frac{576}{625}[/tex][tex]\begin{gathered} \cos ^2(\theta)=\frac{49}{625} \\ \\ \cos ^{}(\theta)=\frac{7}{25} \end{gathered}[/tex]Part 3
Find out the value of tan(theta)
[tex]\tan (\theta)=\frac{\sin (\theta)}{\cos (\theta)}[/tex]substitute given values
[tex]\tan (\theta)=\frac{24}{7}[/tex]