Question

set y=0 and apply the zero product property$y = x {}^{2} + 2x - 3$

Answer 1

Given:

$y=x^2+2x-3$$\begin{gathered} 0=x^2+2x-3 \\ 0=x^2-x+3x-3 \\ 0=x(x-1)+3(x-1) \\ 0=(x-1)(x+3) \end{gathered}$$x=1,-3$