Question

Find the value of x such that the slope of the line containing (x, 5) and (3, -1) is 4.

Answer 1

Given the line containing the points (x, 5) and (3, -1) has a slope of 4

The slope of the line will be:

$\text{slope}=\frac{y_2-y_1}{x_2-x_1}$

Substitution with the given points:

$\frac{5-(-1)}{x-3}=4$

Solve the equation to find x:

$\begin{gathered} 4(x-3)=5-(-1) \\ 4x-12=5+1 \\ 4x=5+1+12 \\ 4x=18 \\ x=\frac{18}{4}=4.5 \end{gathered}$

So, the answer will be x = 4.5