Given the function:
[tex]9^x=6[/tex]
Apply the laws of exponents
[tex]xln(9)=ln(6)[/tex]
And solve for x:
[tex]\begin{gathered} x=\frac{ln(6)}{ln(9)} \\ x=\frac{ln(6)}{2ln(3)} \end{gathered}[/tex]
As a decimal form:
[tex]x=0.815[/tex]
Answer: A. The solution set is
[tex]\frac{ln(6)}{2ln(3)}[/tex]
