Answer:
7
Step-by-step explanation:
This function can never equal 0. Why? well here:
(f/g)(x) also just means [tex]\frac{f(x)}{g(x)}[/tex]. In this case, we get [tex]\frac{x^2-x-12}{x-4}[/tex] Or [tex]\frac{(x+3)(x-4)}{x-4}[/tex]. It seems like you can cancel out x-4 and bam, you get x+3 and any value should work.
However, x can never equal 4 because 4 leads to a case where you divide by 0. This is called discontinuity. Thus, the value you can't get is x=4, or 7 because when you plug 4 in, you get 0/0. Otherwise, any other real value is defined by x+3.
