[tex]\begin{gathered} \frac{-15d^3-50d^2-25d}{5d^3} \\ \\ common\text{ factor is 5d} \\ \frac{5d(-3d^2-10d-5)}{5d(d^2)}=\frac{5d}{5d}\cdot\frac{-3d^2-10d-5}{d^2}=1\cdot\frac{-3d^2-10d-5}{d^2} \\ \\ =\frac{-3d^2-10d-5}{d^2} \\ \text{Hence} \\ \frac{-15d^3-50d^2-25d}{5d^3}=\frac{-3d^2-10d-5}{d^2} \end{gathered}[/tex]
