four inches of a (somewhat magnified ) ruler is shown. use the ruler to give the length of the gray bar, to the nearest sixteenth of an in. write answer as a mixed #. (simplify as much as possible)

We have the following:
We have that 4 is equal to 64/16
[tex]\frac{4\cdot16}{1\cdot16}=\frac{64}{16}[/tex]Thefore:
The bar is found in 2 and 15 more lines, each line is 1/16
[tex]\frac{2\cdot16}{1\cdot16}+\frac{15}{16}=\frac{32}{16}+\frac{15}{16}=\frac{47}{16}=2\frac{15}{16}[/tex]