Question

The perimeter of a rectangle is 52. The length is 2 more than 2 times the width. Find the width and length.

Answer 1

Formula for the perimeter of a rectangle = 2(L + W).
let the width be x
length = 2 + 2x
substitute respectively
52 = 2(2 + 2x + x)
52 = 2 (2 + 3x)
52 = 4 + 6x
52 - 4 = 6x
48 = 6x
divide both sides by 6
48/6 = 6x/6
8 = x
width = 8
length = 2 + 2x = 2 + 2(8) = 2 + 16 = 18