Respuesta :

D

1) Considering the function, let's find out their Limits:

[tex]\begin{gathered} \lim _{t\to0}\mleft(4t^4-4^t\mright)= \\ 4(0)^4-4^0 \\ 0-(1) \\ -1 \end{gathered}[/tex]

Note that we've plugged into that function, t=0.

2) Now let's check for the 2nd option, following some properties on Limits we have:

[tex]\begin{gathered} \lim _{t\to\infty}(4t^4-4^t)= \\ 4t^4-4^t= \\ \lim _{t\to\infty}(4t^4-4^t)=4(4t^4\mleft(1-\frac{4^t}{4t^4}\mright)) \\ \\ 4\cdot\lim _{t\to\infty\: }\mleft(t^4\mleft(1-\frac{4^t}{4t^4}\mright)\mright) \\ \\ \lim _{t\to\infty}(t^4)=\infty \\ \lim _{t\to\infty}(1-\frac{4^t}{4t^4})=-\infty \\ 4\cdot\infty\cdot\mleft(-\infty\: \mright)=-\infty \end{gathered}[/tex]

Note that we've used the property of the product of Limits, then calculated each párt of the function separately.

3) And now, let's find out the roots. In a geometric way. Since the roots are the points in which the graph intercepts the y-axis, we have:

Just one root.

Hence, the answer is D

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