Given the function:
[tex]f(x)=-\sqrt[]{x+3}-2[/tex]So, the square root must be greater than or equal zero
The domain of the function is all the values that are possible for x
so,
[tex]\begin{gathered} x+3\ge0 \\ x\ge-3 \end{gathered}[/tex]So, the domain = x ≥ -3
The range is all the possible value of y when we substitute with x
So, the range will be:
[tex]y\le-2[/tex]So, the answer is option 3