We have the following:
mechanic A:
[tex]A=20\cdot n[/tex]mechanic B:
[tex]B=15\cdot n+50[/tex]now,
[tex]A>B[/tex]replacing:
[tex]\begin{gathered} 20\cdot n>15\cdot n+50 \\ 20n-15n>50 \\ 5n>50 \\ n>\frac{50}{5} \\ n>10 \end{gathered}[/tex]therefore, after 10 hours the valuse for B is less