Answer:
81.8%
Step-by-step explanation:
Mean = [tex]\mu = 40[/tex]
Standard deviation = [tex]\sigma = 5[/tex]
Now we are supposed to find out what percent of the numbers fall between 35 and 50
[tex]z = \frac{x-\mu}{\sigma}[/tex]
Substitute the values
[tex]z = \frac{x-40}{5}[/tex]
Now for P(35<x<50)
Substitute x = 35
[tex]z = \frac{35-40}{5}[/tex]
[tex]z =-1[/tex]
Substitute x = 50
[tex]z = \frac{50-40}{5}[/tex]
[tex]z =2[/tex]
So, P(-1<z<2)
P(z<2)-P(z<-1)
=0.9772-0.1587
=0.8185
= [tex]0.818 \times 100[/tex]
=81.8%
Hence 81.8% percent of the numbers fall between 35 and 50