Question

A submarine descends 480 feet in 24 seconds The elevation change of the submarine after 8 seconds is [ ] feet

Answer 1

Given data:

The given distance is d=480 feet.

The given time is t=24 seconds.

The speed of the submarine is,

$\begin{gathered} s=\frac{d}{t} \\ s=\frac{480\text{ ft}}{24\text{ s}} \\ =20\text{ ft/s} \end{gathered}$

The expression for the change in elevation after 8 seconds is,

$\begin{gathered} D=s\times(8\sec ) \\ =(20\text{ ft/s)(8 s)} \\ =160\text{ ft} \end{gathered}$

Thus, the change in elevation after 8 seconds is 160 ft.