Question

Find the 29th term of an arithmetic sequence with a1 = 2 and d=5

Answer 1

Recall that the nth term of an arithmetic sequence is as follows:

$a_n=a_1+(n-1)d.$

Therefore the nth term of the given sequence is:

$a_n=2+(n-1)*5.$

Evaluating the above result at n=29 we get:

$a_{29}=2+(29-1)*5$

Simplifying the above result we get:

$\begin{gathered} a_{29}=2+28*5 \\ =2+140=142. \end{gathered}$

Answer: 142.