Answer:
the acceleration due to gravity, g is zero (0)
the time of the motion is 0.2 s
Explanation:
Given;
initial velocity of the student, u = 15 m/s
distance traveled by the student, x = 3 m
The motion of the student is directed towards the horizontal and the acceleration due to gravity, g is zero (0).
The time of the motion is calculated as;
x = ut + ¹/₂gt²
x = ut + ¹/₂(0)t²
x = ut
t = x/u
t = 3 / 15
t = 0.2 s
Therefore, the time of the motion is 0.2 s
