The diameter of the base of the cone = 4 ft
The radius of the base of the cone, r = 4/2 = 2 ft
Slant height, l = 6ft
[tex]\text{ Surface area of a cone = }\pi r^2+\pi rl[/tex]
Where r = radius of the base, l = slant height
[tex]\begin{gathered} \text{surface area of the cone = (3.14 x 2 x 2) + (3.14 x }2\text{ x 6)} \\ =\text{ 12.56 + 37.68} \\ =50.24ft^2\text{ }\approx50.2ft^2\text{ (nearest tenth)} \\ \text{The surface area of the cone is 50.2ft}^2\text{ ( to the nearest tenth)} \end{gathered}[/tex]
