Question

At the present time a man is four times as old as his son. Six years ago he was 10 times as old. Find their present ages.

Answer 1

Present Age:-

Son = x

Man = 4x

Six years ago:-

Son = (x - 6)

Man = (4x - 6)

And, we have also been given a relation between the age of son and man six years ago, that is, six years ago, the age of man was 10 times that of the age of son. Using that relation, we can set up an equation as follows:

(4x - 6) = 10(x - 6)

→ 4x - 6 = 10x - 60

→ 10x - 4x = 60 - 6

→ 6x = 54

→ x = 9

And we have assumed that present age of Son is x years and that of man is 4x years. Hence:

• Present age of son = x years = 9 years
• Present age of man = (4x) years = (4 * 9) years = 36 years

Answer 2

Hope it helps! Please mark me as brainliest! Thank you