Answer:
System A: Consistent independent - Unique Solution: (-3,3)
System B: Inconsistent - No solution
System C: Consistent dependent - Infinite solutions
Step-by-step explanation:
Let's evaluate each system:
System A:
The system A has a unique solution, since lines intersect at 1 point. For this reason, the system is consistent indepent.
We can find the solution for this system since the values for x and y are the same at insection point:
[tex]\begin{gathered} Line1\colon y_1_{}\text{=-}\frac{1}{2}x+\frac{3}{2} \\ Line2\colon y_2\text{ =-x} \\ If\text{ }y_1\text{=}y_2 \\ Then \\ \text{-}\frac{1}{2}x+\frac{3}{2}=-x \\ -\frac{1}{2}x+x=-\frac{3}{2} \\ \frac{-x+2x}{2}=-\frac{3}{2} \\ \frac{x}{2}=-\frac{3}{2} \\ x=-\frac{3}{2}\cdot2 \\ x=-\frac{6}{2} \\ x=-3 \\ \\ Since\text{ y=-x} \\ \text{If x=-3 } \\ \text{Then y=-(-3)} \\ y=3 \end{gathered}[/tex]
Solution: (-3,3).
System B:
In this system, we have two parallel lines (same slope). So, the lines will never intersept each other.
For this reason, this system is incosistent and has no soluton.
System C:
The lines 1 and 2 are the same line.
For this reason, the system is consistent dependent and have infinite solutions.