From the given information, we can draw the following picture:
where the widht is three-fourths the length, denoted by x. So, the perimeter (P) is given as
[tex]P=x+x+\frac{3}{4}x+\frac{3}{4}x[/tex]which gives
[tex]\begin{gathered} P=2x+\frac{6}{4}x \\ P=\frac{14}{4}x \end{gathered}[/tex]Since the perimeter is 70 feet, we have
[tex]\frac{14}{4}x=70[/tex]so x is given as
[tex]x=\frac{70\times4}{14}=20[/tex]This means that the length measure 20 feet and the width measures:
[tex]\text{ width=}\frac{3}{4}(20)=15\text{ ft}[/tex]Therefore, the width measures 15 ft.