Question

Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.

Answer 1

The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:
$F=qE=(8.1 \cdot 10^{-9}C)(9.4 \cdot 10^7 N/C)=0.76 N$

Answer 2

C.) 7.6×10^-1 :) your welcome