Question

In the triangle below, if AC = 21 m, CP =18 m, and AB = 20 m, find the area of the triangle ABC.

Answer 1

We can find the area as follows:

$\begin{gathered} A=\frac{1}{2}bh \\ where: \\ b=AB=20 \\ h=CP=18 \\ so: \\ A=\frac{1}{2}(20)(18) \\ A=\frac{360}{2} \\ A=180m^2 \end{gathered}$

Answer:

b. 180 m^2