[tex]\begin{gathered} g(x)=3x^2+5 \\ \\ g(6)=3(6)^2+5 \\ g(6)=3(36)+5 \\ g(6)=105+5 \\ g(6)=110 \\ \\ g(\text{ -3\rparen= 3\lparen-3\rparen}^2+5 \\ g(\text{ -3\rparen=3\lparen9\rparen + 5} \\ g(\text{ -3\rparen=27 +5} \\ g(\text{ -3\rparen = 32} \end{gathered}[/tex]
You have to replace the value given (-6 and 3) for x in the function. Then, you'll have the value.
g(6) = 110
g(-3)= 32
