Respuesta :
Answer:
The root of 16 is 4 and the root of 9 is 3.
Step-by-step explanation:
For the first instance, 16+9 is 25 and the root of that is 5. But for the second one, we have to first find the roots. So 4+3 which equals 7. These are obviously not equal. Does this make sense? Hope that helps.
Answer:
Step 1: Justify
Solve the first one
[tex]\sqrt{16+9}[/tex] → [tex]\sqrt{25}[/tex]
[tex]\sqrt{25}[/tex] → [tex]5[/tex]
Solve the second one
[tex]\sqrt{16} + \sqrt{9}[/tex] → [tex]\sqrt{4^2} + \sqrt{3^2}[/tex]
[tex]\sqrt{4^2} + \sqrt{3^2}[/tex] → [tex]4+3[/tex]
[tex]4+3[/tex] → [tex]7[/tex]
So...
[tex]5\neq 7[/tex]