Respuesta :

Answer:

The root of 16 is 4 and the root of 9 is 3.

Step-by-step explanation:

For the first instance, 16+9 is 25 and the root of that is 5. But for the second one, we have to first find the roots. So 4+3 which equals 7. These are obviously not equal. Does this make sense? Hope that helps.

Answer:

Step 1:  Justify

Solve the first one

[tex]\sqrt{16+9}[/tex] → [tex]\sqrt{25}[/tex]

[tex]\sqrt{25}[/tex] → [tex]5[/tex]

Solve the second one

[tex]\sqrt{16} + \sqrt{9}[/tex] → [tex]\sqrt{4^2} + \sqrt{3^2}[/tex]

[tex]\sqrt{4^2} + \sqrt{3^2}[/tex] → [tex]4+3[/tex]

[tex]4+3[/tex] → [tex]7[/tex]

So...

[tex]5\neq 7[/tex]