[tex]f(x)=\frac{5\text{-5x}}{-6}\text{{\operatorname{\lparen}\text{3rd opt}\imaginaryI\text{on}\operatorname{\rparen}}}[/tex]
Explanation:[tex]\begin{gathered} Given: \\ 5x\text{ - 6y = 5} \\ \\ We\text{ will make y the subject of formula by performing some operations} \end{gathered}[/tex]
subtract 5x from both sides of the equation:
[tex]\begin{gathered} 5x\text{ - 5x - 6y = 5 - 5x} \\ 0\text{ - 6y = 5 - 5x} \\ -6y\text{ = 5 - 5x} \end{gathered}[/tex]
Divide both sides by -6:
[tex]\begin{gathered} \frac{-6y}{-6}\text{ = }\frac{5\text{ - 5x}}{-6} \\ y\text{ = }\frac{5\text{-5x}}{-6} \end{gathered}[/tex]
The question asked that we replace y with f(x):
[tex]f(x)\text{ = }\frac{5\text{ - 5x}}{-6}\text{ \lparen3rd option\rparen}[/tex]
