The unit price is obtained as follows:
[tex]\frac{16.80\text{ \$}}{80\text{ ft of wire}}=0.21\frac{\text{ \$}}{\text{ ft of wire}}[/tex]Then, 20 ft of wire cost:
[tex]20\text{ ft of wire}\cdot0.21\frac{\text{ \$}}{\text{ ft of wire}}=4.2\text{ \$}[/tex]She would pay $4.2 for the extra 20 feet of wire