Question

18. Polar Bear Frozen Foods manufactures frozen French fries for sale to grocery store chains. The final package weight is thought to be a uniformly distributed random variable. Assume X, the weight of French fries, has a uniform distribution between 50 ounces and 68 ounces. What is the mean weight for a package? What is the standard deviation for the weight of a package? Round your answers to four decimal places, if necessary.

Answer 1

Answer:

μ = 59, σ = 5.1962

Step-by-step explanation:

For a uniform distribution, where a is the minimum and b is the maximum, the mean (or average) is:

μ = (a + b) / 2

And the standard deviation is:

σ = (b − a) / √12

Here, a = 50 and b = 68.

The mean is:

μ = (50 + 68) / 2

μ = 59

And the standard deviation is:

σ = (68 − 50) / √12

σ = 5.1962