Find the slope, x-intercept, and y-intercept for the line 10x-7y + 7 = 0. The slope is The I-intercept is h The y-intercept is Note: Your answers must be decimals. Submit Question Jump to Answer

slope=1.43
y-intercept=1
x-intercept=-1.43
Explanation
Step 1
get the slope intercept form of the equation
[tex]y=mx+b\text{ (slope intercept equation)}[/tex]where
m is the slope and b is the y-intercept
to do this, isolate y
[tex]\begin{gathered} 10x-7y+7=0 \\ \text{subtract 10 x in both sides} \\ 10x-7y+7-10x=0-10x \\ -7y+7=-10x \\ \text{subtract 7 in both sides} \\ -7y+7-7=-10x-7 \\ -7y=-10x-7 \\ divide\text{ both sides by -7} \\ \frac{-7y}{-7}=\frac{-10x}{-7}-\frac{7}{-7} \\ y=\frac{10x}{7}+1 \end{gathered}[/tex]so,
[tex]\begin{gathered} \text{slope}=\frac{10}{7} \\ y-\text{intercept}=1 \end{gathered}[/tex]Step 2
to find the x-intercept replace the y value with zero in the equation
[tex]\begin{gathered} y=\frac{10x}{7}+1 \\ 0=\frac{10x}{7}+1 \\ \text{subtract 1in both sides} \\ 0-1=\frac{10x}{7}+1-1 \\ \frac{10x}{7}=-1 \\ \text{Multiply both sides by 7/10} \\ \frac{10x}{7}\cdot\frac{7}{10}=-1\cdot\frac{7}{10} \\ x=-\frac{7}{10} \end{gathered}[/tex]so, the x intercept is
[tex]-\frac{7}{10}[/tex]I hope this helps you