Question

Use the position equation given below, where s represents the height of the object (in feet),
v0
represents the initial velocity of the object (in feet per second),
s0
represents the initial height of the object (in feet), and t represents the time (in seconds), as the model for the problem.
s = −16t2 + v0t + s0
You drop a coin from the top of a building. The building has a height of 1028 feet.
(a) Use the position equation to write a mathematical model for the height of the coin.
s = ?

(b) Find the height of the coin after 1.5 seconds.
s = ? ft

(c) How long does it take the coin to strike the ground? (Round your answer to two decimal places.)
t = ? sec

(I really can't comprehend how to due this but its due soon, please help me!)

Answer 1

Using the motion equation we can get:

a) s = -16*t^2 + 1028

b) 992 feet above the ground.

c) after 8 seconds, the coin will hit the ground.

How to write the height equation?

First, we know that the general height equation is:

s = -16*t^2 + v0*t + s0

In this case, the coin is dropped, so the initial velocity v0 is zero.

And the coin is dropped from a height of 1028 ft, then s0 = 1028

Replacing that in the equation we get:

s = -16*t^2 + 1028

b) The height after 1.5 seconds is what we get by evaluating the height equation in t = 1.5

s = -16*(1.5)^2 + 1028 = 992

This means that the height after 1.5 seconds is 992 ft above the ground.

c) The coin will strike the ground when s = 0, then we need to solve:

s = 0 = -16*(t)^2 + 1028

Solving that for t, w eget:

16*t^2 = 1028

t^2 = 1028/16

t = √(1028/16) = 8

This means that the coin will hit the ground after 8 seconds.

If you want to learn more about motion equations:

https://brainly.com/question/19365526

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