Question

S GP Two spheres having masses M and 2 M and radii R and 3R, respectively, are simultaneously released from rest when the distance between their centers is 12R. Assume the two spheres interact only with each other and we wish to find the speeds with which they collide.(b) Write an equation from one of the models and solve it for →v₁ , the velocity of the sphere of mass M at any time after release in terms of →v₂, the velocity of 2 M .

Answer 1

Let,

$v_{1 i} a n d v_{2 i}$  be the two spheres of the speed before impact

$v_{1 f} a n d v_{2 f}$ be the speed after impact.

By using the law of conservation of linear momentum,

$0=M v_{1 f}+(2 M) v_{2 f} v_{2 f}=-\frac{1}{2} v_{1 f} \cdots \cdots(1) v_{1 f}=-2 v_{2 f}$

The negative sign indicates the sphere approaches each other.

What is the  law of  conservation of linear momentum?

The conservation of momentum states that, within a few problem domain, the quantity of momentum stays constant; momentum is neither created nor destroyed, however only modified thru the movement of forces as defined through Newton's laws of motion. Dealing with momentum is extra tough than coping with mass and energy due to the fact momentum is a vector quantity having each a magnitude and a direction. Momentum is conserved in all 3 physical directions on the identical time. It is even extra tough whilst coping with  gas due to the fact forces in one path can have an effect on the momentum in any other path due to the collisions of many molecules

To learn more about linear momentum, visit;

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