Question

If anyone can help, I'd appreciate it. I feel that the answer is the third option but I am not 100% certain.

Given the exponential function f (x) and the logarithmic function g(x), which of the following statements is true?

Exponential function f of x equals negative 4 to the power of x minus 1 that decreases to the right passing through the point 0 comma negative 2 and logarithmic function g of x equals negative log in base 3 of x plus 3 decreasing from left to right passing through the point 1 comma 3

As x→∞, f (x)→∞ and g(x)→0.
As x→∞, f (x)→ –∞ and g(x)→ –∞.
As x→∞, f (x)→2 and g(x)→0.
As x→∞, f (x)→2 and g(x)→∞.

Answer 1

The true statement about the functions is (b) as x→∞, f (x)→ –∞ and g(x)→ –∞

How to determine the true statements?

The functions are given as:

f(x) = -4^x - 1

g(x) = -log3(x + 3)

Also, the graphs of the functions f(x) and g(x) are given

From the graphs, we have the following highlights:

• As x approaches infinity in g(x), the function approaches negative infinity
• As x approaches negative infinity in g(x), the function approaches 0
• As x approaches infinity in f(x), the function approaches negative infinity
• As x approaches negative infinity in f(x), the function approaches -1

Hence, the true statement about the functions is (b) as x→∞, f (x)→ –∞ and g(x)→ –∞.

Read more about function end behaviors at:

https://brainly.com/question/17206971

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