Respuesta :
A: 5,7 is the point 3 : 2 of the way from R to S
B: 13,11 is the point 4 : 1 of the way from R to S
Let point (x, y) divides the line segment whose end points are ([tex]x_1, y_1[/tex]) and
([tex]x_2, y_2[/tex]) in ratio [tex]m_1 : m_2[/tex], then
[tex]x = \frac{x_1m_2 + x_2m_1}{m_1 + m_2}[/tex] and
[tex]y = \frac{y_1m_2 + y_2m_1}{m_1 + m_2}[/tex]
Solving for A:
According to the question, RS is the line segment with end points R (-3, 3) and S (17, 13) and point (5, 7) divides in the ratio [tex]m_1 : m_2[/tex]
By using the above ratio formula:
[tex]5 = \frac{-3m_2 + 17m_1}{m_1 + m_2}[/tex]
⇒ [tex]5m_1 + 5m_2 = -3m_2 + 17m_1[/tex]
⇒ [tex]5m_2 + 3m_2 = 17m_1 - 5m_1[/tex]
⇒ [tex]8m_2 = 12m_1[/tex]
⇒ [tex]\frac{m_1}{m_2} = \frac{12}{8}[/tex]
⇒ [tex]\frac{m_1}{m_2} = \frac{3}{2}[/tex]
⇒ [tex]m_1 : m_2[/tex] = 3 : 2
Solving for B:
According to the question, RS is the line segment with end points R (-3, 3) and S (17, 13) and point (13, 11) divides in the ratio [tex]m_1 : m_2[/tex]
By using the above ratio formula:
[tex]13 = \frac{-3m_2 + 17m_1}{m_1 + m_2}[/tex]
⇒ [tex]13m_1 + 13m_2 = -3m_2 + 17m_1[/tex]
⇒ [tex]13m_2 + 3m_2 = 17m_1 - 13m_1[/tex]
⇒ [tex]16m_2 = 4m_1[/tex]
⇒ [tex]\frac{m_1}{m_2} = \frac{4}{1}[/tex]
⇒ [tex]m_1 : m_2[/tex] = 4 : 1
∴ Point (5, 7) divides the line segment RS in the ratio 3 : 2.
∴ Point (13, 11) divides the line segment RS in the ratio 4 : 1.
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