Respuesta :

gmany

[tex]f(x)=2x,\ g(x)=\sqrt{x}\\\\(f\circ g)(x)=2\sqrt{x}\\\\The\ domain:\\\\\boxed{x \geq 0}[/tex]

Answer:

Domain is [tex]x\geq 0[/tex]

Step-by-step explanation:

[tex]f(x)= 2x[/tex]

[tex]g(x)=\sqrt{x}[/tex]

Now find (fog)(x)

[tex](fog)(x)= f(g(x))[/tex]

Plug in square root (x) for g(x)

[tex](fog)(x)= f(g(x))=f(\sqrt{x})[/tex]

Now we plug in sqrt(x) for x in f(x)

[tex](fog)(x)= f(g(x))=f(\sqrt{x})=2\sqrt{x}[/tex]

To find out the domain , we find the domain of 2square root (x)

To find domain of square root function , we set x>=0

Domain is [tex]x\geq 0[/tex]

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