PLEASE HELP (100PTS)
In the figure shown, m∠THV=(16x+20)∘, m∠THX=53∘, and m∠XHV=(12x−9)∘.

What is the value of x?

Enter your answer in the box.

PLEASE HELP 100PTS In the figure shown mTHV16x20 mTHX53 and mXHV12x9 What is the value of x Enter your answer in the box class=

Respuesta :

Answer:

x = 6

Step-by-step explanation:

• ∠THX and ∠XHV have a common side HX and a common vertex H

This means they are two adjacent angles.

Then

m∠THX + m∠XHV = m∠THV

Then

53 + 12x−9 = 16x + 20

Solving the equation:

53 + 12x−9 = 16x + 20

⇔ (53 − 9) + 12x = 16x + 20

⇔ 44 = 16x - 12x+ 20

⇔ 44 - 20 = 4x

⇔ 24 = 4x

[tex]\Longleftrightarrow x = \frac{24}{4} =6[/tex]

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