A particle of charge 4.42 x 10^6 C is 9.70 cm distant from a second particle of charge 1.88 x 10^6 C. Calculate the magnitude of the electrostatic force between the particles.

Respuesta :

The magnitude of the electrostatic force between the given two charged particles is 7.94x10^24 N.

The electrostatic force is the force of attraction or repulsion between two charged particles. It is also called Coulomb’s force or Coulomb’s interaction.

F=k x q1xq2/ r^2

The charge of a particle (q1) = 4.42x10^6 C

The charge of the second particle (q2) = 1.88 x 10^6 C

distance between the two particles = 9.70 cm = 0.097m

k = coulomb constant= 9*10^9 kg

electrostatic force between the (F) = ?

F=  9 x 10^9 x 4.42x10^6 x 1.88 x 10^6 / (0.097)^2

F = 7.94x10^24 N (here N = Newton,which is the unit of force)

Learn more about electrostatic force here:

https://brainly.com/question/9774180

#SPJ4

ACCESS MORE
EDU ACCESS