The pH at 25°c of a 0. 0077 m solution of a weak base with a kb of 6. 2 × 10−9 is 8.8.
The base dissociation constant is termed as Kb. Throughout a base split into ts constituent ions in water is determined by its base dissociation constant.
Kb = [B+] [OH-]/[BOH]
Now, let the concentration of [B+] = [OH-] = x
Given,
Kb = 6. 2 × 10^-9
6. 2 × 10^-9 = x^2/(0.0077-x)
x = 6.909 × 10^(-6)
[B+] = [OH-] = 6.909 × 10^(-6)
As we know that,
pOH = -log [OH-]
pOH = -log( 6.909 × 10^(-6))
pOH = 5.2
As we also know that,
pOH + pH = 14
pH = 14 - pOH
pH = 14 - 5.2
pH = 8.8
Thus we calculated that the pH of the solution is 8.8.
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