Question

A 600-kg car makes a 90° turn. its speed before the turn is 21. 0 m/s and after the turn it is 24. 0 m/s. what is the magnitude of the change in the car's momentum during the turn?

Answer 1

The magnitude of the change in the car's momentum during the turn is

$= 1.9 \times 10 {}^{3} kgm/s$

What is momentum?

Momentum can be defined as "mass in motion." All objects have mass,so if an object is moving, then it has momentum - it has its mass in motion.

Given:

V1=21m/s

V2=24m/s

m=600kg

To Find:

momentum

Now using Pythagoras theorem

$f = ((600)(21)) {}^{2} + ((600)(24)) {}^{2}$

$f = \sqrt{1.59 \times 10 {}^{8} + 2.07 \times 10 {}^{8} }$

$= 1.9 \times 10 {}^{3} kgm/s$

learn more about momentum from here: https://brainly.com/question/28165726

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