Question

At what points does the curve r(t) = t i + (4t − t2) k intersect the paraboloid z = x^2 + y^2?
(smaller t-value) (x, y, z) = ?
(larger t-value) (x, y, z) = ?

Answer 1

The points are known to intersect the curve at

• (smaller t-value) (x, y, z) = 0, 0, 0
• (larger t-value) (x, y, z) = 2, 0, 4

How to find the points

We have our equation as: r(t)=ti+(4t-t2)k (4t - t2)k

From  r(t)

We have x to be t, y to be 0 and z=4t-t2

The given paraboloid can be defined to be

z=x^2+y^2

We are to put the values in the equation

4t-t²=t²+0

2t²=4t

Then t wuld be 2 or 0

Hence we have to conclude that ours points of intersection are at (0,0,0) and (2,0,4).

The 0,0,0) and (2,0,4) points is where the intersection of the paraboloid take place.

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