Question

what is the equation of the line that contains point (2, -6) and has a slope of -2

y= -2x + 10
y= -2x + 2
y= -2x - 2
y= -2x -10

Answer 1

Answer:

y=-2x+10

Step-by-step explanation:

i graphed it i graphed all of them

Answer 2

Answer:

y-2x-2

Step-by-step explanation:

The way I would do this is by first using the information given and making an equation in point-slope form, before bringing it to y=mx+b.

We know that the slope is -2, and we have a point, (2,-6). The formula for equations in point slope form is $y-y_{1} =m(x-x_{1} )$. So, we can insert the given information into this formula to get $y+6=-2(x-2)$.

Next, we distribute the slope to the the parenthesis to get $y+6=-2x+4$

Then, we subtract 6 from both sides to get $y=-2x-2$

Since this equation is now in the form $y=mx+b$, the answer is $y-2x-2$

Hope this helps! :)