Please help me solve this, random answers will be removed.

Answer:
See below
Step-by-step explanation:
Here is one way .... I showed you how to use Law of cosines in another Q
use this to find CB
CB^2 = 13^2 + 21^2 - 2(13)(21) cos 91 <==== solve for CB
THEN use law of SINES to find angle B
sin B / 21 = sin 91 / CB (CB you found using law of cosines above)
Answer:
m∠B = 57.5°
Explanation:
Use cosine rule:
a² = b² + c² - 2bc cos(A)
inserting values
a² = 21² + 13² - 2(21)(13) cos(91)
a² = 619.529
a = √619.529
a = CB = 24.89 km
Then use sine rule:
sin(A)/a = sin(B)/b
sin(91)/24.89 = sin(B)/21
sin(B) = 21sin(91)/24.89
sin(B) = 0.843583...
B = sin⁻¹(0.843583) = 57.52° ≈ 57.5°