Question

An airplane travels 1350 miles in 5 hours, going against the wind. The return trip is with the wind, and takes only 3.75 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

Answer 1

Solving a system of equations we can see that:

• The airplane rate is 315 mi/h
• The wind rate is 45 mi/h.

How to find the rate of the airplane?

Let's define:

• A = rate of the airplane.
• W = rate of the wind.

When the airplane travels against the wind, the total speed is:

(A - W)

In this way, we know that the airplane travels 1350 miles in 5 hours, then:

(A - W) = 1350mi/5h

When the airplane travels with the wind, it takes 3.75 hours to travel the same distance, then:

(A + W) = 1350mi/3.75h

We have now a system of equations:

(A - W) = 1350mi/5h

(A + W) = 1350mi/3.75h

If we isolate A on the first equation, we get:

A = 270mi/h + W

Replacing that in the other equation we get:

270mi/h + W + W = 360 mi/h

Solving for W we get:

2*W = 360mi/h - 270mi/h = 90mi/h

W = 90mi/h = 45mi/h

And the airplane rate is:

A =  270mi/h + W = 270mi/h + 45mi/h = 315 mi/h

If you want to learn more about systems of equations:

https://brainly.com/question/13729904

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