Answer:
[tex]f(x)= log_3(x+2)-5[/tex]
Step-by-step explanation:
Parent function is [tex]g(x)= log_3(x)[/tex]
LEts pick a point from the graph and check with each option
LEts pick (-1,-5)
[tex]f(x)= log_3(x-2)-1[/tex]
[tex]f(x)= log_3(-1-2)-1[/tex]
log term cannot be negative
[tex]f(x)= log_3(x-3)-2[/tex]
[tex]f(x)= log_3(-1-3)-2[/tex]
log term cannot be negative
[tex]f(x)= log_3(x+2)-5[/tex]
[tex]f(x)= log_3(-1+2)-5[/tex]
[tex]f(x)= log_3(1)-5[/tex], log(1) is 0
f(x)= -5 that is the y value
(-1,-5) satisfies the above equation