Question

A pizza shop advertises that it puts 0.5 pounds of real mozzarella cheese on its medium pizzas. In addition, it is discovered that the quantity of cheese put on the population of all medium pizzas has a normal distribution with mean 0.495 and standard deviation 0.025. Calculate the minimum number of pounds of mozzarella cheese necessary to say that your medium pizza ranked in the top 3% of all medium pizzas in terms of cheese content.

Answer 1

The minimum number of pounds of mozzarella cheese is necessary to say that your medium pizza ranked in the top 3% of all medium pizzas in terms of cheese content.

P(z < 0.2) = 0.5793

What is a normal distribution?

Generally, The normal distribution, also known as the Gaussian distribution, is a kind of probability distribution that is symmetric around the mean. This means that it demonstrates that data that are closer to the mean are more likely to occur than data that are farther away from the mean. When represented graphically, the normal distribution takes the shape of a "bell curve."

In conclusion, To begin, we calculate the z score to determine the crucial value. If

$z =\frac{ (x - u)}{ s}$

x = critical value = 0.5

u = mean = 0.495

Hence

$z =\frac{ (x - u)}{ s}$

z= 0.2

Therefore, by making use of a table or some other kind of technology, the left-tailed area of this is

P(z < 0.2) = 0.5793

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Complete Question

A pizza shop advertises that it puts 0.5 pounds of real mozzarella cheese on its medium pizzas. In addition, it is discovered that the quantity of cheese put on the population of all medium pizzas has a Normal distribution with a mean of 0.495 and standard deviation 0.025. The probability that a randomly selected pizza has less than the advertised amount of mozzarella cheese is:

a) 0.2000

b) 0.5793

c) 0.4207

d) 0.800