Question

A car travelling at 3.50 m/s [w] speeds up to 14.8 m/s [w] in 3.17 s. determine the acceleration of the car.

Answer 1

The acceleration of the car is 3.56 m/s².

What is acceleration?

Rate of change of velocity with time, both in terms of speed and direction. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Some characteristics of acceleration are-

• Acceleration is a vector quantity since it has a both magnitude and a direction.
• A vector quantity is also velocity. The velocity vector change during a time interval divided by that of the time interval is the definition of acceleration.
• The limit of both the ratio of the change in speed throughout a given interval of time approaches zero determines the instantaneous acceleration (at the specific time and location) ( Instantaneous rates of change).
• For instance, acceleration will be stated as metres per second if velocity is represented in meters per second.

The formula for acceleration is;

$\bar{a}=\frac{v-v_{0}}{t}=\frac{\Delta v}{\Delta t}$

$\begin{aligned}&\bar{a}=\text { average acceleration } \\&v=\text { final velocity } \\&v_{0}=\text { starting velocity } \\&t=\text { elapsed time }\end{aligned}$

The starting velocity is 3.50 m/s

The final velocity is 14.8 m/s.

The elapsed time is 3.17 s.

Substitute all the values in the formula of acceleration;

$\bar{a}=\frac{14.8-3.50}{3.17}\\\bar{a}=3.56$

Therefore, the acceleration of the car is 3.56 m/s².

To know more about acceleration, here

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