Nacl has a delta.hfus = 30.2 kj/mol. what is the mass of a sample of nacl that needs 732.6 kj of heat to melt completely? use q equals n delta h.. 24.3 g 82.7 g 1,407.1 g 1,417.7 g

Respuesta :

The correct value is 1417.7 grams.

The mass of a sample of Nacl that needs 732.6 kj of heat to melt completely is 1417.7 grams.

What is Enthalpy of fusion?

Enthalpy of fusion is the quantity of heat energy needed to turn a unit mass of the a solid now at melting point into such a liquids without raising the temperature.

Some key point for enthalpy of fusion of melting ice are-

  • The quantity of heat energy required to convert solid stuff into liquid is known as the heat of fusion (melting.)
  • Q = mHf is the formula for calculating heat of fusion.
  • The temperature is not a part of the equation or the computation because matter does not truly change temperature when it changes states.
  • The fusion heat is usually a positive value, with the exception of when melting helium

Calculation for the heat required-

Nacl has a delta.hfus = 30.2 kj/mol => [tex]\Delta H_{\text {fusion }}=30.2 \mathrm{~kJ} / \mathrm{mol}[/tex]

As a result, the enthalpy of fusion for 1 mole of sample NaCl is 30.2 kJ.

Additionally, the mass of 1 mole for NaCl is 58.44 grams.

For a quantity of 58.44 grams of NaCl, 30.2 kJ of heat are required.

Consequently, 732.6 kJ heat will be required for;

[tex]\frac{58.44 g}{30.2 k J} \times 732.6 k J=1417.65 \approx 1417.7[/tex] grams of NaCl.

Therefore, the mass of a sample of Nacl that needs 732.6 kj of heat to melt completely is 1417.7 grams of NaCl.

To know more about enthalpy of fusion, here

https://brainly.com/question/14096901

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