Question

A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?
A. 3
B.0
C.-3
D. pi/4

Answer 1

Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

Given the following data:

• Amplitude = 3

• Period = π

• Phase shift = π/2

How to determine the y-intercept of this function?

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

Where:

• A represents the amplitude.

• ω represents angular velocity.

• t represents the period.

• ø represents the phase shift.

Also, the period of a sine wave is given by:

t = 2π/ω

2 = 2π/ω

ω = 2

Substituting the given parameters into the equation, we have;

y = 3sin(2t + π/2)

At t = 0, we have:

y = 3sin(2(0) + π/2)

y = 3sin(π/2)

y = 3sin(90)

y = 3 × 1

y = 3.

In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.

Read more on phase shift here: https://brainly.com/question/27692212

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